$
\newcommand{\bmat}[1]{\left[\begin{array}{#1}}
\newcommand{\emat}{\end{array}\right]}
\newcommand{\coll}[2]{\bmat{r} #1 \\ #2 \emat}
\newcommand{\colll}[3]{\bmat{r} #1 \\ #2 \\ #3 \emat}
\newcommand{\red}[1]{{\color{red}#1}}
\newcommand{\lra}[1]{\mbox{$\xrightarrow{#1}$}}
\newcommand{\rank}{\textrm{rank}}
\newcommand{\mystack}[2]{\genfrac{}{}{0}{0}{#1}{#2}}
\newcommand{\mystackthree}[3]{\mystack{\mystack{#1}{#2}}{#3}}
$

The solutions manual solves this question for a different vector,
and the answer at the back of the book also uses the wrong vector.
Below are the answer and solution for the correct vector.
The correct answer is that $d = 9$.

The check vector for ISBN-10 is $\vc = [10,9,8,7,6,5,4,3,2,1]$.
The given vector is $\vu = [0, 3, 9, 4, 7, 5, 6, 8, 2, d]$.

The dot product $\vc \cdot \vu = 246+d = 4+d \pmod{11}$, so
if you take $d = 7$, the total is $11$, which is $0 \pmod{11}$.